The
room table contains a list of rooms with the following information:HNO |
ROOMTYPE |
MAX_FREE |
PRICE |
10 |
double |
45 |
200.00 |
10 |
single |
20 |
135.00 |
20 |
double |
13 |
100.00 |
20 |
single |
10 |
70.00 |
30 |
double |
15 |
80.00 |
30 |
single |
12 |
45.00 |
40 |
double |
35 |
140.00 |
40 |
single |
20 |
85.00 |
50 |
double |
230 |
180.00 |
50 |
single |
50 |
105.00 |
50 |
suite |
12 |
500.00 |
60 |
double |
39 |
200.00 |
60 |
single |
10 |
120.00 |
60 |
suite |
20 |
500.00 |
70 |
double |
11 |
180.00 |
70 |
single |
4 |
115.00 |
80 |
double |
19 |
150.00 |
80 |
single |
15 |
90.00 |
80 |
suite |
5 |
400.00 |
90 |
double |
145 |
150.00 |
90 |
single |
45 |
90.00 |
90 |
suite |
60 |
300.00 |
100 |
double |
24 |
100.00 |
100 |
single |
11 |
60.00 |
110 |
double |
10 |
130.00 |
110 |
single |
2 |
70.00 |
120 |
double |
78 |
140.00 |
120 |
single |
34 |
80.00 |
120 |
suite |
55 |
350.00 |
130 |
double |
300 |
270.00 |
130 |
single |
89 |
160.00 |
130 |
suite |
100 |
700.00 |
140 |
double |
9 |
200.00 |
140 |
single |
10 |
125.00 |
140 |
suite |
78 |
600.00 |
150 |
double |
115 |
190.00 |
150 |
single |
44 |
100.00 |
150 |
suite |
6 |
450.00 |
The room table is linked to the
hotel table via the hotel number.SQL statement for creating the table structure
CREATE TABLE room
(hno FIXED(4) KEY,
roomtype CHAR(6) CONSTRAINT roomtype IN ('single', 'double', 'suite'),
max_free FIXED(3) CONSTRAINT max_free>=0,
price FIXED(6,2) CONSTRAINT price BETWEEN 0.00 AND 1000.00)